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Finding flux from cube

  1. Jul 18, 2016 #1
    1. The problem statement, all variables and given/known data
    Consider an electric field E = 2x i - 3y j. The coordinate x and y are measured in meters and the electric field is in N/C. What is the magnitude of the flux of this field through a square whose corners are located at (x,y,z) = (0,2,0), (2,2,0), (2,2,2), (0,2,2)?

    2. Relevant equations
    Our proffesor gave us the answer of 24. He's been wrong before so I'm not sure. The choices are 6, 12, 24, 0, 48.

    3. The attempt at a solution
    https://gyazo.com/bb9e4506b7124f7704ab9e0393f6d7f8
    I did this in math cad. I've never done double integrals and I need some help. Thanks!
     
    Last edited: Jul 18, 2016
  2. jcsd
  3. Jul 18, 2016 #2

    SammyS

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    Here is your Math Cad image:
    upload_2016-7-18_17-16-42.png

    It looks like your square only has 3 corners. I suppose the missing corner is at (2,2,2).

    What is the definition of flux? It should include a scalar product (dot product).
     
  4. Jul 18, 2016 #3
    I edited the original post. Sorry, I miss typed! It is at (2,2,2).
    The definition of flux is the integral of electric field doted with area. What am I doing wrong in mathcad?
     
  5. Jul 18, 2016 #4

    SammyS

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    What is the normal vector to the area ?
     
  6. Jul 18, 2016 #5
    Would the normal vector be flux? I'm not sure.
     
  7. Jul 18, 2016 #6

    SammyS

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    No. You need a vector to associate with the area, so that you can take the dot product of that vector and the electric field.

    The surface of the square is parallel to the x-z plane. What unit vector is normal to that square?
     
  8. Jul 18, 2016 #7
    j? I'm not searching for someone to do the problem for me, but I'm pressed for time as we were given this extra credit assignment today, so if you could just solve this and explain the steps you took, I would really appreciate it. The only reason I am asking is because of my time constraint.
     
  9. Jul 18, 2016 #8
    I get that the flux goes through the j hat direction, so you take (3*2) = 6 and then multiply it by the area (2*2) and get 24. But my teacher wants us to solve this using a double integral in math cad for bonus points. I've never done double integrals so I just need an example or someone to do it and show me how..
     
  10. Jul 18, 2016 #9

    SammyS

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    That's a self contradictory statement.

    It's against PF rules to provide you with a solution. The best we can do is to help you to solve this yourself.

    How do you describe the area over which you integrate? ... in addition to being normal to ##\ \hat{j}\ ##
     
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