1. The problem statement, all variables and given/known data An 88 kg man drops from rest on a diving board 3.3m above the surface of the water and comes to rest 0.58 seconds after reaching the water. Acceleration due to gravity is 9.81 m/s^s What force does the water exert on the man? in N 2. Relevant equations F = ma a = v/t 3. The attempt at a solution 3.3/0.58 = 5.689655172 m/s = v F = 88 * 5.689655172 = 500.6896552 N F = 500.6896552 N Did I do this right?