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Finding force

  1. Nov 20, 2007 #1
    A 57.0 kg person jumps from rest off a 11.0 m high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 3.00 m under the surface of the water. Determine the average force that the water exerts on the diver. This force is nonconservative.

    i know to use mgh=Fd... i think... but i dont know what distance or height to use or when you are supposed to incorporate the 3.00 m

    any help would be apprectiated..
     
    Last edited: Nov 20, 2007
  2. jcsd
  3. Nov 20, 2007 #2
    Yeah you're right, mgh = Fd

    The distance that the force from the water acts through is 3m, so distance d = 3m.
    Stick that into the equation and you are done :D
     
  4. Nov 20, 2007 #3
    when i do mgh=fd...

    (57)(9.8)(11)=f(3)
    i get 2048.2 N, but its incorrect. what am i doing wrong?
     
  5. Nov 20, 2007 #4
    The height dropped in the fall isn't 11m, it is (11+3)m. Does it work now?
     
  6. Nov 20, 2007 #5
    yes, it worked!
    thanks so much :)
     
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