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Finding gradient vector

  1. Apr 10, 2007 #1
    1. The problem statement, all variables and given/known data
    Find the angle between (grad)u and (grad)v at all points with x!=0 and y!= 0 if
    x =( e^u)*(cos v) and y = (e^u) (sinv) .

    3. The attempt at a solution

    is not here x and y a function of u and v? How are we going to find grad of u and v? Should we pull out u and y from the equations (I mean if x =( e^u)*(cos v)) then u=ln(x/cosv) etc. )
  2. jcsd
  3. Apr 10, 2007 #2
    No, you write u and v in terms of x and y. Here's a hint to start with: sin2x + cos2x = 1
  4. Apr 10, 2007 #3
    thank you very much, ı understand. (ı found the answer as pi/2. I hope it is true)
  5. Apr 10, 2007 #4
    It's certainly true.
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