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Finding height of elevator

  1. Sep 22, 2012 #1
    1. The problem statement, all variables and given/known data

    .An elevator is moving at 1.1 m/s as it approaches its destination floor from below. When the elevator is a distance h from its destination, it accelerates with a = −0.55 m/s2. Find h

    2. Relevant equations

    vf^2=v0^2+2ax

    x=x0+v0t+1/2at^2

    3. The attempt at a solution

    (0m/s^2)=(1.1)^2+2(0.55m/s/s)(x)
    x^2=2.31
    x=1.51 m
     
    Last edited: Sep 22, 2012
  2. jcsd
  3. Sep 22, 2012 #2
    Hi, can you post an attempt at the problem, or describe why you're having trouble solving it?
     
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