# Finding height of elevator

## Homework Statement

.An elevator is moving at 1.1 m/s as it approaches its destination floor from below. When the elevator is a distance h from its destination, it accelerates with a = −0.55 m/s2. Find h

vf^2=v0^2+2ax

x=x0+v0t+1/2at^2

## The Attempt at a Solution

(0m/s^2)=(1.1)^2+2(0.55m/s/s)(x)
x^2=2.31
x=1.51 m

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