A racket ball is struck in such a way that it leaves the racket with a speed of 4.81 m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 1.97 m from the racket. Find the height of the racket ball when it left the racket. okay so what I did was try to find the time so I did x=VoT which is 1.97=4.81t and I got t=.40956.... I think I am on the right path so to find height now can I just do y=gt^2/2 to get my height?