Calculating Height of Racket Ball Leaving Racket

[wadini]

A racket ball is struck in such a way that it leaves the racket with a speed of 4.81 m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 1.97 m from the racket.
Find the height of the racket ball when it left the racket.

okay so what I did was try to find the time so I did x=VoT which is 1.97=4.81t and I got t=.40956... I think I am on the right path so to find height now can I just do y=gt^2/2 to get my height?

 

[rock.freak667]

That should work.

 

[nlightner]

Yes, you are on the right track. To find the height of the racket ball when it left the racket, you can use the equation y=gt^2/2, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time calculated earlier (0.40956 seconds). This will give you the height in meters. However, keep in mind that this calculation assumes a perfectly flat surface and neglects air resistance. In reality, the height of the racket ball may vary slightly due to these factors.