Let [phi](u,v)=(u^2,v). Is phi one-to-one? If not, determine a domain on which phi is one-to-one. Find the image under phi of: - The rectangle R=[-1,1]X[-1,1] 3. The attempt at a solution - I'm not sure at all how to determine whether phi is one-to-one or not, so if somebody can explain that, that would be of great help. I thought I knew how to find the image under phi (because I got the right answers the way I did it on the previous problem), but I'm not getting the right answers on this problem. Please help.