- #1
Greywolfe1982
- 62
- 0
Finding inflection points of x(ln(x)) (or "Why is WolframAlpha telling me this?")
The question is finding the points of inflection for f(x)=xlnx. As far as I know, it has none, and is concave up for the entire function within its domain, x>0. When I look at the graph on WolframAlpha though, it's telling me there's a real part to the function for x<=0. Would somebody care to explain what I'm missing? Or is it a glitch on WolframAlpha's part?
Here's the output:
http://www.wolframalpha.com/input/?i=x(lnx)
The question is finding the points of inflection for f(x)=xlnx. As far as I know, it has none, and is concave up for the entire function within its domain, x>0. When I look at the graph on WolframAlpha though, it's telling me there's a real part to the function for x<=0. Would somebody care to explain what I'm missing? Or is it a glitch on WolframAlpha's part?
Here's the output:
http://www.wolframalpha.com/input/?i=x(lnx)