A basketball player is standing 9.5 m from the basket, which is at a height of 3.1m. she throws the ball from a initial height of 2m at an angle of 35 degrees above the horizontal. The ball goes through the basket. Determine intial velocity.
PS Assume the max height of the parabola of the ball is 1.1 m.
The Attempt at a Solution
I took only half the parabola diagram and assumed v2 is 0 m/s
v1 = ?
v2 = 0 m/s
a = -9.8 m/s^2
max height = 1.1 m
I used the equation
v2^2 = v1^2 + 2ad
and got v1 as 4.64 m/s and from there on on I found initial velocity at an angle.
BUT the textbook gives a different answer (11m/s) as the initial velocity at an angle.
I can't figure out why I'm getting this wrong and my teacher sasys she will come back to me as she can't figure the mistake in mine... so help LOL