- #1

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[itex]lim\sum\limits_{k=1}^{n-1} \frac{k^{2}}{n^{3}}, n\geq 2[/itex]

and

[itex]lim\sum\limits_{k=2}^n \frac{k-1}{k!}, n\geq 2[/itex]

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- Thread starter hamsterman
- Start date

- #1

- 74

- 0

[itex]lim\sum\limits_{k=1}^{n-1} \frac{k^{2}}{n^{3}}, n\geq 2[/itex]

and

[itex]lim\sum\limits_{k=2}^n \frac{k-1}{k!}, n\geq 2[/itex]

- #2

mathman

Science Advisor

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For the second split it into two sums (k and -1 numerators). Compare them with each other. The final answer will be 1 (unless I made a mistake).

- #3

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Thanks a lot, I see now.

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