# Homework Help: Finding limit

1. Aug 16, 2016

### manasi bandhaokar

1. The problem statement, all variables and given/known data
limit (5/(2+(9+x)^(0.5))^(cosecx)
x-->0
attempt:
tried applying lim (1+x)^(1/x) = e.
x->0
couldn't get anywhere.

2. Aug 16, 2016

### Cozma Alex

Try direct substitution

3. Aug 16, 2016

### manasi bandhaokar

wouldn't work.there's a 'cosecx' up there which goes to infinity at x = 0

4. Aug 16, 2016

### Cozma Alex

Ahhh you're right, sorry

5. Aug 16, 2016

### Mastermind01

Is it permissible to use L'hopital's rule?

Last edited: Aug 16, 2016
6. Aug 16, 2016

### manasi bandhaokar

yep.but i would also like to know how to solve it the way i was trying to.i thought abt l'hospital but couldn't figure out how to apply it.

7. Aug 16, 2016

### Mastermind01

You have $\lim_{x\rightarrow 0} ({\frac{5}{2+\sqrt{9+x}}})^{cosec (x)}$

The key idea here is to take the logarithm. Since the logarithm is a continuous function log of the limit is the limit of the log.

So the $e^{\lim_{x\rightarrow 0} \ln({\frac{5}{2+\sqrt{9+x}}})^{cosec (x)}}$

This reduces to $e^{\lim_{x\rightarrow 0}\frac{\ln({\frac{5}{2+\sqrt{9+x}})}}{sin (x)}}$

You can apply l'hopital or use other methods to evaluate the top portion.

P.S - Next time while asking homework questions, use the template.

8. Aug 16, 2016

### haruspex

You can clearly replace the cosec x with 1/x immediately.
If you then transform the $\frac 5{2+\sqrt{9+x}}$ into the form 1+ some fraction, you can substitute x=0 immediately in the denominator of that fraction, and expand the numerator with the binomial theorem.

9. Aug 31, 2016

### manasi bandhaokar

Thanks all for the Help.