Finding limiting reactant

  • Thread starter yjk91
  • Start date
  • #1
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Homework Statement


Procedure
1. Add 25 mL of HCL solution to each flask.
2. Weigh out 0.15g, 0.3g, and 0.6g of Mg ribbon and place each sample into its own balloon




Homework Equations



Mg + 2HCl --> H2 + MgCl2

The Attempt at a Solution



show the calculations determining the limiting reactant for each reaction.

Help on how to get the limiting reactant!!

And using the limiting reactant as the starting amount, determine the amount of hydrogen gas that was produced per reaction flask:
 

Answers and Replies

  • #2
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I think you need to know the molarity of HCl.
 
  • #3
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oh my bad 1.0moles HCL/1L or 0.1 moles HCL/100mL solution
 
  • #4
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Since you know the molarity of HCl to be 1M, you can compute how many moles of HCl you have at 25mL. The formula Molarity = mole/volume in Liter, or mole = Molarity x Volume in liter.
Further, based on your equation, you know you need a 2 HCL to 1 Mg ratio.
So just figure out how many moles of Mg you have at .15g, .3 and .6
From that you can see your limiting reactant.
 

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