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Finding mass of spring (SHM)

  1. Dec 2, 2007 #1
    Hi there, I just want to confirm my answer: A mass "M" is set oscillating on a spring of mass "[tex]m_{s}[/tex]". If the total mass of the system is given by:

    Derive an expression for [tex]m_{s}[/tex].

    Well first off:



    & E = K + U ,where E is constant

    So I just get the time derivative:

    [M+[tex]\frac{m_{s}}{3}[/tex]]a + kv = 0 ,where
    [tex]v = \omega A cos \omega t[/tex]
    [tex]a = -\omega^{2}A sin \omega t[/tex]

    Then I just solve for [tex]m_{s}[/tex]

    I'm pretty sure it's right, but I'd just like some confirmation.
  2. jcsd
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