1. The problem statement, all variables and given/known data You apply a force of .35N up to lift a fork, the resulting acceleration is .15m/s2. What is the mass in grams. Please help I don't know where to start with this simple question.
The net force would not be zero and I am only given the applied force. Without a mass I don't know how I can get the force of gravity. So as far as I can tell I have .35 Fg = m .15m/s2
0.35 Fg = m .15m/s2 0.35 - (m 9.8 m/s2) = m 0.15ms2 The second law says that if the net force is not zero there is an acceleration in the direction of the force.
You apply a force of 0.35 N upward. If the mass of the for is m, what force is gravity exerting downward on the fork? What is the net force being exerted upon the fork?
You will have "m" in two places in your equation. Use algebra to solve for m. I repeat:What is the net force being exerted upon the fork?
I can get up untill Fapp - m a(gravity) / a(applied) = m Now I am a bit confused on my next move. Is this right so far? Since m on the left is being multiplied by the acceleration of gravity I think I should divide to get rid of it. But once I do the right side would cancel out to zero.
F_{app} - m g = m a 0.35 - m g = m (0.15) Not sure what you use for g: 10 m/s^{2} or 9.8 m/s^{2} or 9.81 m/s^{2} Put in the appropriate number for g & solve for m.
Yes, but as I said earlier I can get up until 0.35 - m g / 0.15 = m I can't successfully eliminate the LH m. I tried dividing and adding it to the RH
Before you divide by 'a', your correct equation, per post 5 2nd line, was 0.35 - (m 9.8 m/s2) = m 0.15ms2 leaving off units, then 0.35 - (9.8m) = 0.15m Now this is algebra, add 9.8m to both sides 0.35 = 9.95m Now solve for m and convert to grams.