(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A skier is going up a slope of 5 degrees to the horizontal. She is skating so only her skis provide propoltion. The static and kenetic friction coefficients for this situation are [tex]\mu[/tex][tex]_{s}[/tex]=0.12 and [tex]\mu[/tex][tex]_{k}[/tex]=0.07

Find the magnitude of her maximum possible uphill acceleration.

2. Relevant equations

Net force in the y direction is: Normal force - mg cos 5 deg =0

Therefore Normal force = mg cos 5 deg

Max acceleration: F in x /m = a = -mg sin 5 deg + max static friction/m

3. The attempt at a solution

I then put all my numbers in like so:

Max acceleration= -mg*sin 5 deg + 0.12 (mg*cos 5 deg)/m

the m cancels and using 9.8 for g I got

0.32ms[tex]^{-2}[/tex]

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# Homework Help: Finding max acceleration up a slope with only static friction and kinetic friction

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