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Finding Maximum Height

  1. Sep 14, 2011 #1
    1. The problem statement, all variables and given/known data
    A coin tossed straight up into the air takes
    2.75 s to go up and down from its initial
    release point 1.30 m above the ground.

    What is its maximum height?


    2. Relevant equations


    3. The attempt at a solution



    I seriously have no clue how to do this problem. I really need a detailed explanation with steps. I'm sorry if this doesn't abide by your question standards, but I really mean I have 0 idea how to solve this problem, and I really need some help.


    Thanks.
     
  2. jcsd
  3. Sep 14, 2011 #2
    can anyone help?
     
  4. Sep 14, 2011 #3
    its 1.30 + V0^2/2g

    since V^2=V0^2 + 2g(ay) where the max height is when V=0
     
  5. Sep 14, 2011 #4
    where V0=g(2.75/2) since V= V0 + gt where V=0m/s since you are accounting for the time it takes and the velocity at the point it goes its max height.
     
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