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Finding minimum potential

  1. Oct 11, 2009 #1
    If we have a particle of mass m moving in the presence of the following potential in one dimension:

    V(x) = V0 [(e-2[tex]\gamma[/tex]x) - 2e-[tex]\gamma[/tex]x)]

    In order to find the minimum of the potential V do we take the derivative with respect to x?



    dV(x)/dx = 2*[tex]\gamma[/tex]V0[(e-[tex]\gamma[/tex]x) - (e-2[tex]\gamma[/tex]x)]


    Is this how we find the minimum potential of V?

    And how do we sketch a graph of V?
     
  2. jcsd
  3. Oct 11, 2009 #2

    Office_Shredder

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    A point can only be a minimum of a function if the derivative at that point equals what?
     
  4. Oct 11, 2009 #3
    zero?
     
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