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Finding momentum

  1. Nov 16, 2007 #1
    1. The problem statement, all variables and given/known data

    A 0.12 kg ball of dough is thrown straight up into the air with an initial speed of 20 m/s.
    Acceleration of gravity is 9.81 m/s^2

    What is its momentum halfway to its maximum height on the way up? Answer in kg*m/s
    (Don't worry about sigfigs)
    2. Relevant equations

    hmax= Vi^2 / 2g
    Vf^2 = Vi^2 + 2ad

    3. The attempt at a solution

    hmax = (20)^2 / 2(9.81)
    hmax = 400 / 19.62
    hmax = 20.38735984 m

    Since we are finding the halfway momentum you divide that by 2
    20.38735984 / 2 = 10.19367992 m

    Vf^2 = Vi^2 + 2ad
    Vf^2 = (20)^2 + 2(-9.81)(10.19367992)
    Vf^2 = 400 + - 200
    Vf^2 = 200
    Vf = square root of 200 = 14.14213562 m/s

    p = mv
    p = (0.12)(14.14213562)
    p = 1.697056275 kg*m/s

    Did I do this right?
     
  2. jcsd
  3. Nov 16, 2007 #2
    Yep, now try to find out how you got those two formula?
     
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