- #1

mr_coffee

- 1,629

- 1

E = q/(4PIEoR^2) plugged and chugged and got 3.34E-9 which isn't right of course, where did i screw up?

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- Thread starter mr_coffee
- Start date

- #1

mr_coffee

- 1,629

- 1

E = q/(4PIEoR^2) plugged and chugged and got 3.34E-9 which isn't right of course, where did i screw up?

- #2

Jelfish

- 144

- 5

- #3

Dr.Brain

- 538

- 2

[itex]

E= \frac{kQ}{r^2}

[/itex]

You just need to fill in the values to calculate Q.Since the field is inwards, the charge will be negative.

BJ

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