A long, straight wire has a 11.1‐A current flowing in the positive x -direction, as shown in the figure. Close to the wire is a square loop of copper wire that carries a 1.65‐A current in the direction shown. The near side of the loop is d=50.7cm away from the wire. The length of each side of the square is a=1.31m .
Question: Find the net torque on the loop.
Torque = n*I*A*B*sin θ
The Attempt at a Solution
n, which is the number of windings is 1.
A is the area that the loop encompasses.
However, since there is a wire below the loop with current running through it, how do I account for that in the values of I and B and θ?
Last edited by a moderator: