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Finding net torque on a loop

  • Thread starter nuagerose
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Homework Statement


http://ezto.mhecloud.mcgraw-hill.com/13252699450881445581.tp4?REQUEST=SHOWmedia&media=ch28q44a.jpg [Broken]
A long, straight wire has a 11.1‐A current flowing in the positive x -direction, as shown in the figure. Close to the wire is a square loop of copper wire that carries a 1.65‐A current in the direction shown. The near side of the loop is d=50.7cm away from the wire. The length of each side of the square is a=1.31m .

Question: Find the net torque on the loop.


Homework Equations



Torque = n*I*A*B*sin θ

The Attempt at a Solution



n, which is the number of windings is 1.
A is the area that the loop encompasses.

However, since there is a wire below the loop with current running through it, how do I account for that in the values of I and B and θ?
 
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Answers and Replies

  • #2
CWatters
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