(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find partial fractions for 4/(x^3-2x^2)

3. The attempt at a solution

Heres the steps that I took:

1. 4/(x^3-2x^2)= 4/(x^2(x-2))= A/(x^2) + B/(x-2)

2. 4= A(x-2) + B(x^2)

3. When x=0, -2A=4, so A=-2,

and When x=2, 4B=4, so B=1.

4. So my final answer was:

-2/(x^2)+1/(x-2)

The real answer as I found out from Wolfram Alpha integral calculator was:

-2/(x^2)+1/(x-2)-1/x

So the real answer is the same as the solution that I got, except for the -1/x at the end... I have no idea where that -1/x came from, no matter how many times I redo this problem. Please tell how to get the real answer! Thank you!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Finding Partial Fractions

**Physics Forums | Science Articles, Homework Help, Discussion**