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Homework Help
Calculus and Beyond Homework Help
Finding particular integrals
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[QUOTE="OllyRutts, post: 5465277, member: 526689"] [h2]Homework Statement [/h2] (d^2y/dx^2) + (dy/dx) = cos xSo you have the trial solution y= p*cos(x)+q*sin(x) (dy/dx) = -p*sin(x)+q*cos(x) (d^2y/dx^2)=-p*cos(x)-q*sin(x) The issue I am having is equating the coefficients when after I have subbed them into the initial equation: -p*cos(x)-q*sin(x)-p*sin(x)+q*cos(x)=cos(x) Equating coefficients of sin x gives -q-p=0 Equating coefficients ofcos x gives -p+q=1 My question is why is -q*sin(x)-p*sin(x)=cos(x) = q-p=0and same for equating for cos x? Thanks Olly [/QUOTE]
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Calculus and Beyond Homework Help
Finding particular integrals
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