Find the percent yield of alum
In an experiment to synthesize alum I started with 0.766g of aluminum and made 8.246g of alum
2Al + 6H20 + 2KOH ---> 2KAl(OH)4 + 3H2
The Attempt at a Solution
First I find the LR. Which in this expirment is Al.
I find the moles of aluminum to be 0.02838mol, next I multiply by the mole ratio and by the molar mass of alum to find the theoretical yield of alum.
Now to find the percent yield I do actual/theoretical X100%
8.246g/3.806g x 100% = 217%. I know Im wrong because this is impossible.
What did I do wrong?