1. Nov 3, 2004

dudgey

At a time 2.60 s, a point on the rim of a wheel with a radius of 0.240 m has a tangential speed of 50.0 m/s. as the wheel slows down with a tangential acceleration of constant magnitude 10.7m/s^2 . At what time will the radial acceleration equal 9.810 m/s^2?

I tried using the equation omega final = omega initial + alpha * t.
* I found omega final by 9.81=omega^2*r (probably wrong)
* I converted the given speed to rad/s and used it for omega inital
*Then I used the square root of the two accelerations squared for alpha (also seems wrong, but I can't figure out anything else)
*Then I solved for t and added the given t to it to find a time, but its not right.