A 102-turn, 3.8-cm-diameter coil is made of 0.59-mm diameter copper wire. A magnetic field is perpendicular to the coil. At what rate must B increase to induce a 3.4 A current in the coil? The resistivity of copper is 1.7·10-8 Ω·m.
The Attempt at a Solution
A = (0.00059/2)^2 * pi = 2.734 x 10^-7
I = 3.4 A
I don't what to do???