A number of resistors of values R1 = 5.0 Ω, R2 = 98.0 Ω, and R3 = 16.0 Ω are connected as shown in the figure. What is the resistance between points A and B?
The Attempt at a Solution
Ok so the 4 R_1's and R_3 are in series on the end which gives a resistance of 36.0 ohm. This resistance is in parallel with R_2 so it's 1/ (1/first resistance + 1/R2 ) =26.3ohm. The 4 R1's and R2 are in series so its R1(4)+R2 =118. Now this resistance is in parallel with the first R2 so its 1/ (1/118 +1/98)= 53.5ohm + the 2 R1's at the start = 63.5
So 63.5 ohm + 26.3 ohm = 89.8 ohm but this isnt right. Can someone help me out please.
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