- #1

- 20

- 0

for instance, if the inductance is 50mH and the capacitance is 20nF, how do I achieve a resonant frequency of 200khz? what parameters are involved?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter kautilya
- Start date

- #1

- 20

- 0

for instance, if the inductance is 50mH and the capacitance is 20nF, how do I achieve a resonant frequency of 200khz? what parameters are involved?

- #2

- 12,134

- 161

edit added: I'm assuming the cap and inductor are connected in series. If your setup is otherwise, let us know. Again, a more detailed description generally helps to get a better answer.

- #3

- 7,637

- 2,342

You could probably do the same thing with an electrical circuit- excite with a spark, record the ring-down.

- #4

- 12,134

- 161

If one doesn't have a function generator, just flipping on a switch from a DC source might even suffice.

- #5

- 3

- 0

f=1 / sqr rt(L* C).

// assuming the value of r is very very small.

When the values are substituted, a frequency of nearly 32 KHz is obtained.

Varying the values of C will yield a different bandwidth. To obtain a frequency of 20 KHz; the frequency desired, a different capacitance value could be used.

- #6

- 4,662

- 6

Using 50 millihenrys and 20 nanofarads, I calculate w = 31,623 radians per sec, and f = 5033 Hz. The sqrt(L/C) impedance is 1581 ohms. Put the L and C in parallel, put a 100k resistor in series, and take a signal generator (sine wave ppreferred) and put it across the LC circuit plus resistor, put a high impedance voltmeter across the LC circuit, and run the frequency from manually from 100 Hz to 100 kilohertz. The volts across the LC circuit will rise when you near resonance. See attached pdf for frequency sweep

Share: