I need to find the locations of the singularity of f(z) = Log(2+tan(z)).(adsbygoogle = window.adsbygoogle || []).push({});

So far I have looked at the function in its alternate form

Log(2+tan(z)) = ln(abs(2+tan(z))) + i*Arg(2+tan(z))

If I remember correctly the first part is simple and cannot equal zero.

Now I think the second part is defined on the cut 0 to 2∏ which eliminates the negative imaginary axis.

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# Finding singularities

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