Let f(x) = xe^(2x)
A) Find the values of x for which the slope of the cruve y = f(x) is 0
B) Explain the meaning of your answer to part (a) in terms of the graph f
The Attempt at a Solution
I tried setting xe^(2x) to 0 by making it 0 = xe^(2x). I dont know what to do from there on. Am i supposed to take the derivative of xe^(2x)?