# Finding spring constant.

• tebes

## Homework Statement

The scale is set by Fs = 200 N. We release the block at x = 14.0 cm. How much work does the spring do on the block when the block moves from xi =+8.0 cm to (a)x=+7.0 cm, (b)x=-7.0 cm, (c)x=-8.0 cm, and (d)x=-11.0 cm?
xi= initial point
x= final point

## The Attempt at a Solution

I'm required to obtain K first before proceeding to the next step.
Fs= -kd
k= - Fs/d
= 200/0.14
= 1428.57 N/m

K= spring constant
d=distance
But the answer is wrong. May I know the reason ? Thank you.

The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"?

PhanthomJay said:
The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"?
Thank you very much. I solved this question already. Love you.