Finding spring constant.

  • Thread starter tebes
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  • #1
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Homework Statement


The scale is set by Fs = 200 N. We release the block at x = 14.0 cm. How much work does the spring do on the block when the block moves from xi =+8.0 cm to (a)x=+7.0 cm, (b)x=-7.0 cm, (c)x=-8.0 cm, and (d)x=-11.0 cm?
xi= initial point
x= final point

Homework Equations





The Attempt at a Solution


I'm required to obtain K first before proceeding to the next step.
Fs= -kd
k= - Fs/d
= 200/0.14
= 1428.57 N/m

K= spring constant
d=distance
But the answer is wrong. May I know the reason ? Thank you.
 

Answers and Replies

  • #2
PhanthomJay
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The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"???
 
  • #3
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The wording of the problem is unclear. If it means that when the spring is stretched 14 cm, the force in the spring is 200 N, then your answer is correct. But what is really meant by "the scale is set by Fs = 200 N"???
Thank you very much. I solved this question already. Love you.
 

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