# Finding Tangential Acceleration

1. Oct 31, 2004

### GingerBread27

The flywheel of a steam engine runs with a constant angular speed of 425 rev/min. When steam is shut off, the friction of the bearings stops the wheel in 1.7 h.

At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 50 cm from the axis of rotation?

I know the equation to use is At=(alpha)r, where alpha is dw/dt. In this case I'm not sure how to compute the alpha and I'm sure it's just a simple point that I am missing.

2. Oct 31, 2004

### Spectre5

first change the 1.7 hours to seconds, then the 425 rev/min to rad/s

then:

$$\alpha=\frac{d\omega}{dt}$$

$$\alpha dt=d\omega$$

$$\int_{0}^{t}\alpha dt=\int_{\omega}^{0}d\omega$$

3. Oct 31, 2004

### Staff: Mentor

Use simple kinematics to find alpha: $\alpha = \Delta \omega/\Delta t$. (Take care with your units, as Spectre5 advises.)

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