An energetic father stands at the summit of a conical hill as he spins his 24 kg child around on a 5.7 kg cart with a 2.0-m-long rope. The sides of the hill are inclined at 24 degrees . He keeps the rope parallel to the ground, and friction is negligible What rope tension will allow the cart to spin with the 17 rpm? I know the equation for tension is T= mv^2/R I tried to convert 17 rpms into rad/s and got 1.8 rad/s I got the velocity as 3.6 m/s. I dont know if I did this right but any feedback or corrections would be greatly appreciated.. Thanks!