- #1
c-murda
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[SOLVED] Finding Tensions IS SO FUN
Find tesnions T1, T2, and T3 and M in figure attached...
To start i drew three FBD
A) for mass on left
Fm= T2-m*g = 0
B)the intersection
Fx = T3 cos 37 - T2 cos 63 = 0
Fy = T2 sin 63 + T3 sin 37 - T1 = 0
C) mass of box
F = T1 - mg
so...
C) box
T1 = (6.00kg)*(9.80m/s^2) = 58.8 N
B) Intersection
.799T3 - .454T2 = 0
.891T2 +.602T3 = 58.8N
.891T2 + .602[((.454/)(.799))*(T2))] = 58.8
1.23T2= 58.8N
T2= 58.8/1.23= 47.8N
T3 = ((.454/)(.799))*(T2); = ((.454/)(.799))*(47.8); T3 = 26.8
A) T2/g = m (47.8N)/(9.80 m/s^2) = m = 4.87kg
Homework Statement
Find tesnions T1, T2, and T3 and M in figure attached...
Homework Equations
The Attempt at a Solution
To start i drew three FBD
A) for mass on left
Fm= T2-m*g = 0
B)the intersection
Fx = T3 cos 37 - T2 cos 63 = 0
Fy = T2 sin 63 + T3 sin 37 - T1 = 0
C) mass of box
F = T1 - mg
so...
C) box
T1 = (6.00kg)*(9.80m/s^2) = 58.8 N
B) Intersection
.799T3 - .454T2 = 0
.891T2 +.602T3 = 58.8N
.891T2 + .602[((.454/)(.799))*(T2))] = 58.8
1.23T2= 58.8N
T2= 58.8/1.23= 47.8N
T3 = ((.454/)(.799))*(T2); = ((.454/)(.799))*(47.8); T3 = 26.8
A) T2/g = m (47.8N)/(9.80 m/s^2) = m = 4.87kg