Here's the question: the rotor of a helicopter starts from REST and reaches it's operating speed in 7.28s If the angular acceleration of the rotor is 92.5 rad/s^2, what is the angular displacement during that time? I'm not sure where to start. If I multiply the time by the acceleration I would get the velocity only in rad/s. But then I was thinking more like: Angular position= 1/2 (angular acceleration) *t^2+(initial angular velocity)*t+(initial angular position) If I plug them into the angular position formula I get 2451.176 rad Is the angular displacement a fancy way to say angular position?? Is this the right track to be on?