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the rotor of a helicopter starts fromRESTand reaches it's operating speed in7.28sIf the angular acceleration of the rotor is92.5 rad/s^2, what is the angular displacement during that time?

I'm not sure where to start.

If I multiply the time by the acceleration I would get the velocity only in rad/s.

But then I was thinking more like:

Angular position= 1/2 (angular acceleration) *t^2+(initial angular velocity)*t+(initial angular position)

If I plug them into the angular position formula I get 2451.176 rad

Is the angular displacement a fancy way to say angular position??

Is this the right track to be on?

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# Homework Help: Finding the angular displacement

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