- #1

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[tex]y=e^{4x}[/tex]

[tex]y=e^{6x}[/tex]

first thing i did was set them equal to each other and multiply by [tex]ln[/tex] which got me 4x=6x, that's where i got stuck. how would i find the x-intercepts?

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- Thread starter ProBasket
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- #1

- 140

- 0

[tex]y=e^{4x}[/tex]

[tex]y=e^{6x}[/tex]

first thing i did was set them equal to each other and multiply by [tex]ln[/tex] which got me 4x=6x, that's where i got stuck. how would i find the x-intercepts?

- #2

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what do you mean? what area? function doesn't have area.....

EDIT:

These two function intersect at 1 point (0,1) only...

EDIT:

These two function intersect at 1 point (0,1) only...

Last edited:

- #3

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ProBasket said:

[tex]y=e^{4x}[/tex]

[tex]y=e^{6x}[/tex]

first thing i did was set them equal to each other and multiply by [tex]ln[/tex] which got me 4x=6x, that's where i got stuck. how would i find the x-intercepts?

1. You can't

2. The exponential function is strictly increasing over the whole real line. There's no way it takes the same value twice (unless its of the form e^{periodic function} which it isn't in your case).

3. Drawing proper graphs for both functions referred to the same set of orthogonal axes might help. How fast do the functions grow?

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- #4

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ProBasket said:

[tex]y=e^{4x}[/tex]

[tex]y=e^{6x}[/tex]

first thing i did was set them equal to each other and multiply by [tex]ln[/tex] which got me 4x=6x, that's where i got stuck. how would i find the x-intercepts?

[tex]Area = \int_{x_1}^{x_2} ( e^{6x} - e^{4x} ) \delta x [/tex]

where [tex]x_1[/tex] and [tex]x_2[/tex] should found from

[tex]e^{4x} = e^{6x}[/tex]

Last edited:

- #5

HallsofIvy

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