A 68 kg man drops to a concrete patio from a window only 0.60 m above the patio. He neglects to bend his knees on landing, taking 2.0 cm to stop. What is the magnitude of the average stopping force? -From this problem I have already found that the average acceleration is 293.95 m/s^2. I tried to find the average force by using the formula F=ma. F=68kg(293.95m/s^2)=199988 N. However that is not right. I need is a formula to compute the average stopping force. Thank you.