1. The problem statement, all variables and given/known data A science-fair radio uses a homemade capacitor made of two 45 45 sheets of aluminum foil separated by a 0.30-mm-thick sheet of paper. Assume dielectric constant of paper is 3.0. What is its capacitance? 2. Relevant equations C=k e0 A / d 3. The attempt at a solution I'm not sure if this is the wrong formula or if I am supposed to double .45m since there are two plates. Anyways, I came up with this... (3.0) * (8.85*e-12) * (.45) / .0003 But the answer I came up with is wrong. Can anyone steer me in the right direction?