The question is: A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.00 m, 3.00 m) with a velocity of -5.00 m/s and an acceleration of +10.0 m/s2. What are the coordinates of the center of the circular path? I know centripical acceleration is a = (v^2)/r I know: ax = 0 m/s^2 ay = 10 m/s^2 and . . . vx = -5 m/s vy = 0 m/s where do i go from here?