In moving out of a dormitory at the end of the semester, a student does 2.69 x 104 J of work. In the process, his internal energy decreases by 5.52 x 104 J. Determine each of the following quantities (including the algebraic sign): (a)W, (b) delta U, and (c)Q. I get the following using formula: delta U = Q - W (a) 2.69E4 J (b) -5.52E4 J (c) -28300 J I know that part a and c are right, but part b isn't for some reason I do not understand. I think it should be right, but it marks it wrong. It's probably the easiest problem I've ever encountered, but for some reason I'm having trouble getting it. Does anyone know what the answer should be?