First, I said that the distance between the two spheres is 0.0523m since you can form a right triangle using 0.5m [50cm] as the hypotonose, and 3 degrees as an angle. and multiplying that answer by 2 giving me the distance between the two spheres.

From that I know one sphere = 2q, while the other sphere = q.

So... F = (K)(q)(2q) / (r^2)

From there i'm stuck, since you have two unknowns (charge 'q' and force 'F')

I'm thinking of using F=ma = 0 (a=0), then finding using a Free Body diagram to find the force on each sphere and adding them and setting them to zero?

So sphere 1 and 2's forces = mg, tension, Electric Force (F/q)
where the Forces are equal?

I'm not too sure, can anyone give me any suggestions? Thanks for any help.

1.The 2 charges have to have opposite charge signs,else they wouldn't repel each other and would not make an angle of 6°.
2.The charges need to be in equilibrium,which means they have total acceleration zero,this meaning that the net force acting one each other is zero.
3.Write Newton's principle for each charge,knowing the 3 forces that act on each of them.
4.Use projections of forces on axes of coordinates conveninetly chosen and geomtry of the figure to find the unknowns.

and one sphere = equilibrium, created a right triangle with mg, Tension, and Electrical force. Knowing [mg] and the angles, I solved for the Electrical Force.

Then set that = to (k)(2q)(q) / r^2, where r = 0.0523 and k = 9x10^9.