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Finding the conjugate of psi

  1. Sep 8, 2009 #1
    1. The problem statement, all variables and given/known data

    Find the conjugate of

    [tex] \varphi[/tex]=[tex]exp(-x^2/x_0^2)[/tex]
    2. Relevant equations



    3. The attempt at a solution


    Isn't the conjugate [tex] \varphi[/tex]*=[tex]exp(x^2/x_0^2)[/tex]
     
  2. jcsd
  3. Sep 8, 2009 #2

    Dick

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    Not if x and x0 are real, which I suspect they are. What is it in that case?
     
    Last edited: Sep 8, 2009
  4. Sep 8, 2009 #3
    oh ,my solution would only be correct if x/x0 is imaginary.would my expression
    [tex]
    exp(-x^2/x_0^2)
    [/tex] not change when taking its conjugate??
     
  5. Sep 8, 2009 #4

    Dick

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    Right, sort of. If x is imaginary the conjugate(exp(x))=exp(-x). If x is real then conjugate(exp(x))=exp(x). But your solution is only correct if (x/x0)^2 is purely imaginary.
     
  6. Sep 8, 2009 #5
    but x/x0 is not purely imaginary , but completely real. So my expression would remain the same when taking its conjugate
     
  7. Sep 8, 2009 #6

    Dick

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    Yesss.
     
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