Finding the conjugate of psi

noblegas

1. The problem statement, all variables and given/known data

Find the conjugate of

$$\varphi$$=$$exp(-x^2/x_0^2)$$
2. Relevant equations

3. The attempt at a solution

Isn't the conjugate $$\varphi$$*=$$exp(x^2/x_0^2)$$

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Dick

Homework Helper
1. The problem statement, all variables and given/known data

Find the conjugate of

$$\varphi$$=$$exp(-x^2/x_0^2)$$
2. Relevant equations

3. The attempt at a solution

Isn't the conjugate $$\varphi$$*=$$exp(x^2/x_0^2)$$
Not if x and x0 are real, which I suspect they are. What is it in that case?

Last edited:

noblegas

Not if x and x0 are real, which I suspect they are. What is it in that case?
oh ,my solution would only be correct if x/x0 is imaginary.would my expression
$$exp(-x^2/x_0^2)$$ not change when taking its conjugate??

Dick

Homework Helper
oh ,my solution would only be correct if x/x0 is imaginary.would my expression
$$exp(-x^2/x_0^2)$$ not change when taking its conjugate??
Right, sort of. If x is imaginary the conjugate(exp(x))=exp(-x). If x is real then conjugate(exp(x))=exp(x). But your solution is only correct if (x/x0)^2 is purely imaginary.

noblegas

Right, sort of. If x is imaginary the conjugate(exp(x))=exp(-x). If x is real then conjugate(exp(x))=exp(x). But your solution is only correct if (x/x0)^2 is purely imaginary.
but x/x0 is not purely imaginary , but completely real. So my expression would remain the same when taking its conjugate

Dick

Homework Helper
but x/x0 is not purely imaginary , but completely real. So my expression would remain the same when taking its conjugate
Yesss.

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