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Engineering and Comp Sci Homework Help
Finding the Current Source of an RLC AC Circuit
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[QUOTE="axmls, post: 5498565, member: 488930"] This is correct. Notice that both ends of the voltage source and the capacitor are connected together. Your first result for ##I_c## is correct. Your second is incorrect because you applied current division incorrectly. With current division, the numerator will be the branch that you're [I]not[/I] interested in (try your hand at deriving it for fun). Try it again and see if you get the same result. Small point: while you do obtain the correct value, you have written your equation for the impedance of a capacitor incorrectly. It should be $$Z_c = \frac{-j}{\omega C}$$ or $$Z_c = \frac{1}{j \omega C},$$ not ##Z_c = 1/(-j \omega C)##. This is because ##1/j = -j##. [/QUOTE]
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Finding the Current Source of an RLC AC Circuit
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