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Finding the Derivative.

  1. Nov 8, 2006 #1

    i need some assistance on this problem:

    y = e^(1+lnx)

    1st. I brought down the (1+lnx) by using natural log on both sides.



    what do i do next?
  2. jcsd
  3. Nov 8, 2006 #2


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    [tex]e^{1+\ln x}=e^1e^{\ln x}=ex[/tex]
  4. Nov 8, 2006 #3
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