# Finding the Derivative.

1. Nov 8, 2006

hello,

i need some assistance on this problem:

y = e^(1+lnx)

1st. I brought down the (1+lnx) by using natural log on both sides.

lny*y'=(1+lnx)*lne
y'/y=(1/x)*1

y'=e^(1+lnx)*(1/x)

what do i do next?

2. Nov 8, 2006

### quasar987

$$e^{1+\ln x}=e^1e^{\ln x}=ex$$

3. Nov 8, 2006