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Homework Help: Finding the Derivative.

  1. Nov 8, 2006 #1
    hello,

    i need some assistance on this problem:

    y = e^(1+lnx)

    1st. I brought down the (1+lnx) by using natural log on both sides.

    lny*y'=(1+lnx)*lne
    y'/y=(1/x)*1

    y'=e^(1+lnx)*(1/x)

    what do i do next?
     
  2. jcsd
  3. Nov 8, 2006 #2

    quasar987

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    [tex]e^{1+\ln x}=e^1e^{\ln x}=ex[/tex]
     
  4. Nov 8, 2006 #3
    thanks,!!:tongue2:
     
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