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Finding the directions of eigenvectors symmetric eigenvalue problem
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[QUOTE="PeroK, post: 6467535, member: 493650"] When we talk about eigenvectors, we are really taking about eigenspaces. Each eigenvalue has an eigenspace of one or more dimensions associated with it. No single vector is [I]the[/I] eigenvector. In this case, you have a 1D eigenspace associated with each eigenvalue. The author has chosen normalised ##v_1, v_2##, which limits the choice to ##\pm v_1, \pm v_2##. In complex vector spaces, a normalised eigenvector is determined only up to a complex "phase factor" of unit modulus. E.g. a normalised eigenvector can take the form ##\alpha v##, where ##v## is a normalised eigenvector and ##\alpha## is any complex number of unit modulus. And, of course, real numbers of unit modulus reduces to ##\pm 1##. [/QUOTE]
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Finding the directions of eigenvectors symmetric eigenvalue problem
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