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1. What is the displacement between t= 0 s and t= 7 s?The "area' under the curve, between the two times is the displacement. The "area" is the area enclosed by the curve and the time axis (v=0 line). Those parts of the curve with negative velocity contribute negative area and those with positive velocity contribute positive area.

Between t=0 s and 7 s,

Δx =

2. Relevant equations

Area of Rectangle: (l*w)

Area of Trapezoid: (1/2 b (h1+h2))

Area of Triangle: (1/2bh)

3. Rectangle: 1.5(-380)= -570

Trapezoid:1/2*3*(-380+-280)=-825

Triangle: 1/2*1.5*280=-420

delta x = -(570+825+420)= -1815 ...this was my attempt and it was wrong. I don't know what I am doing wrong please help

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Finding the displacement under a curve. Please Help

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