So:

t = 1.77s

vi = 0m/s

acc = 9.8 m/s^2 (Due to gravity, correct?)

d = ?

I'm suspecting that I use the distance formula of:

d= vit + 1/2 at^2

so that the height is:

15.35m?

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I apologize for the simplicity of the problem, but I'd really appreciate help.