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I'm not too sure if this is the correct location for my post, but it's the best fit I can see!

The cdf of the continuous random variable X is

[tex]F(x)=\left\{\begin{array}{cc}0&\mbox{ if }x< 0\\

{1\over 4} x^2 & \mbox{ if } 0 \leq x \leq 2\\

1 &\mbox{ if } x >2\end{array}\right.[/tex]

Q1-Obtain the pdf of X

Q2-If Y = 2 - X, derive the pdf of the random variable Y

A1-I think the cdf is given by [tex]f(x) = F'(x)=\left\{\begin{array}{cc}{1\over 2}x &\mbox{ if } 0 \leq x \leq 2 \\

0 &\mbox{ elsewhere } \end{array}\right.[/tex]

Is that correct?

A2-For the pdf of Y: [tex]G(Y) = P(Y \leq y) = P(2 - x \leq y) = P(x \geq 2-y)

[/tex] but I'm not sure how to proceed??

Thanks

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