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Finding the electric field

  1. Feb 10, 2016 #1
    1. The problem statement, all variables and given/known data

    An object with charge q = −4.00×10−9 C is placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right, it has kinetic energy 5.00×10−7 J .What is the magnitude of the electric field?
    2. Relevant equations
    U = kQ/r^2
    F = Eq
    W = Fd
    U = Eqd

    3. The attempt at a solution
    I was thinking that I could maybe set the voltage difference equal to the electric field * charge * distance since the part before asked that if the electric potential at point A is +30.0 V, what is the electric potential at point B? Which the answer was 155 V.
     
  2. jcsd
  3. Feb 10, 2016 #2

    haruspex

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    By what logic, theory, or standard equation is a potential equal to field x charge x distance?
     
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