Hi there, I have to complete the following question, but I have no idea how to approach it (there are four other parts to the question that I can't complete until I get the first bit). I have made numerous attempts, but am not sure how to get the a part of the equation. All help would be appreciated! Thanks, Kafka Question A curve f(x) is defined by the equation : y = ax² + bx + c, where a, b and c are constants. The curve crosses the y-axis at the point (0,4). At this point the gradient of the graph is -5. The curve crosses the x-axis at point (1,0). (i) Find the values of a, b, and c and write down the equation of the curve Attempt Sub point (0.4) into equation to get c (x=0,y=4): y = ax² + bx + c 4 = 0 + 0 + c c = 4 If gradient at point (0,4) is -5, then dy/dx must be equal to -5. dy/dx = 2ax + b -5 = 2ax + b -5 = 2a(0) + b -5 = 0 + b b = -5 *not sure about the bit below* c=-5, b=4, so sub these into equation of curve and use a point to find a y = ax² + bx + c at (1,0) x=1, y=0 y = ax² + bx + c 0 = a1² + (-5 x 1) + 4 0 = a -5 + 4 0 = a - 1 a = 1 ???