An aluminum beam 79 m long and with a cross-sectional area of 0.095 m2 is used as part of a bridge. The beam is clamped rigidly at both ends.
(a) If the temperature of the beam is increased by 29°C, what is magnitude of the extra force exerted by the beam on one of its supports?
(b) What is the magnitude of the force if the temperature of the beam is decreased by 43°C?
delta L = alpha of alum (a constant) * L * temp
Force = Young's Modulus of alum * area * delta L / L
The Attempt at a Solution
delta L = (22.2x10^-6)*(79m)*(302 K) = .53m
F= (7.0x10^10)*(.095m^2)*(.53m)/(79m) = 4.46x10^7
Unfortunately, that was incorrect.
Because I couldn't get the first part correct, I haven't been able to attempt b, but I'm assuming you do the same thing but change the temp in the first equation.